# JAMB Further Mathematics Questions And Answers 2024

This article is for all the JAMB candidates who will be writing Further mathematics in during the forthcoming examination. JAMB Further Mathematics Questions and Answers 2024 is special guide on how you can write the JAMB examination and score above 3000.

A lot of persons have been write JAMB but unable to get their desired scores at the end. If you are one these set of persons, all you have to do is to take every information that you are going to come across in this article very serious.

Table of Contents

## JAMB Further Mathematics Questions and Answers 2024

The following are the expected likely questions and answers for JAMB Further Mathematics. Feel excited to prepare yourself with these questions if you are a candidate of the forthcoming examination.

1

If $$log_{y}\frac{1}{8}$$ = 3, find the value of y.

• A. -2
• B. -$$\frac{1}{2}$$
• C. $$\frac{1}{2}$$
• D. 2

Correct Answer: Option C

logy18=3⟹y3=18����18=3⟹�3=18 (Laws of logarithm)

y3=123=(12)3�3=123=(12)3

Equating both sides, we have

y=12

2

A binary operation $$\Delta$$ is defined on the set of real numbers, R, by $$a \Delta b = \frac{a+b}{\sqrt{ab}}$$, where a$$\neq$$ 0, b$$\neq$$ 0. Evaluate $$-3 \Delta -1$$.

• A. $$-4\sqrt{3}$$
• B. $$\frac{-4\sqrt{3}}{3}$$
• C. $$\frac{-3\sqrt{3}}{4}$$
• D. $$\frac{-3\sqrt{3}}{4}$$

Correct Answer: Option B

aΔb�Δ� = a+bab√�+���

−3Δ−1−3Δ−1 = −3+−1−3×−1√−3+−1−3×−1

−43√−43, rationalising, we have

−4×3√3√×3√=−43√3

3

Simplify $$\frac{1}{(1-\sqrt{3})^{2}}$$

• A. $$1- \frac{1}{2}\sqrt{3}$$
• B. $$1+ \frac{1}{2}\sqrt{3}$$
• C. $$\sqrt{3}$$
• D. $$1+\sqrt{3}$$

Correct Answer: Option B

$$a \Delta b$$ = $$\frac{a+b}{\sqrt{ab}}$$

$$-3\Delta -1$$ = $$\frac{-3 + -1}{\sqrt{-3\times -1}}$$

$$\frac{-4}{\sqrt{3}}$$, rationalising, we have

$$\frac{-4 \times \sqrt{3}}{\sqrt{3}\times \sqrt{3}} = \frac{-4\sqrt{3}}{3}$$

4

If $$x^{2} – kx + 9 = 0$$ has equal roots, find the values of k.

• A. 3, 4
• B. $$\pm3$$
• C. $$\pm5$$
• D. $$\pm6$$

Correct Answer: Option B

1(1−3√)21(1−3)2

(1−3–√)2=(1−3–√)(1−3–√)(1−3)2=(1−3)(1−3)

1−23–√+3=4−23–√1−23+3=4−23

14−23√14−23

After rationalising (multiplying the denominator and numerator with 4+23–√4+23, we have

4+23√4=1+123–√

5

Find the coordinates of the centre of the circle $$3x^{2}+3y^{2} – 4x + 8y -2=0$$

• A. (-2,4)
• B. ($$\frac{-2}{3}, \frac{4}{3}$$)
• C. ($$\frac{2}{3}, \frac{-4}{3}$$)
• D. (2, -4)

See also: 2024 JAMB Physics for Day One

JAMB Biology Questions And Answers 2024

6

If(19)2x−1=(181)2−3x(19)2�−1=(181)2−3�find the value of x

• A. −58−58
• B. −34−34
• C. 3434
• D. −58−58

Correct Answer: Option D

(19)2x−1=(181)2−3x(19)2�−1=(181)2−3�

(19)2x−1=(19)2(2−3x)(19)2�−1=(19)2(2−3�)

(19)2x−1=(19)4−6x(19)2�−1=(19)4−6�

Since the bases are equal, powers can be equated

= 2x – 1 = 4 – 6x

= 2x + 6x = 4 + 1

= 8x = 5

∴x=58

7

The table shows the operation * on the set {x, y, z, w}.

Find the identity of the element.

• A. W
• B. Y
• C. Z
• D. X

Correct Answer: Option C

From the table, x * z = x, y * z = y, z * z = z and w * z = w

∴ z is the identity element

8

Find the radius of the circle 2×2+2y2−4x+5y+1=02�2+2�2−4�+5�+1=0

• A. 3√34334
• B. 5√656
• C. 5656
• D. 334334

Correct Answer: Option A

Standard Form equation of a circle (Center-Radius Form): (x−a)2+(y−b)2=r2(�−�)2+(�−�)2=�2

Where “a” and “b” are the coordinates of the center and “r” is the radius of the circle

2×2+2y2−4x+5y+1=02�2+2�2−4�+5�+1=0

Divide through by 2

= x2+y2−2x+52y+12=0�2+�2−2�+52�+12=0

=x2−2x+y2+52y=−12�2−2�+�2+52�=−12

=x2−2x+12+y2+52y+(54)2−1−2516=−12�2−2�+12+�2+52�+(54)2−1−2516=−12

=(x−1)2+(y+54)2=−12+1+2516(�−1)2+(�+54)2=−12+1+2516

=(x−1)2+(y−(−54))2=3316(�−1)2+(�−(−54))2=3316

=(x−1)2+(y−(−54))2=(3√34)2(�−1)2+(�−(−54))2=(334)2

∴a=1,b=−54and∴�=1,�=−54��� r3√34(answer)

9

Given that M is the midpoint of T (2, 4) and Q (-8, 6), find the length of MQ .

• A. √26units√26�����
• B. √28units√28�����
• C. √24units√24�����
• D. √30units√30�����

10

A particle began to move at 27ms−127��−1 along a straight line with constant retardation of 9ms−29��−2. Calculate the time it took the particle to come to a stop.

• A. 3 sec
• B. 2 sec
• C. 4 sec
• D. 1 sec

11

Find the fifth term in the binomial expansion of (q+x)7(�+�)7.

• A. 21q2x521�2�5
• B. 21q4x321�4�3
• C. 35q3x435�3�4
• D. 35q5x235�5�2

12

Given that P = {x : 2 ≤ x ≤ 8} and Q = {x : 4 < x ≤ 12} are subsets of the universal set μ = {x : x ∈ R}, find (P ⋂ Q11).

• A. {x : 4 < x < 8}
• B. {x : 2 < x ≤ 4}
• C. {x : 2 ≤ x ≤ 4}
• D. {x : 4 ≤ x ≤ 8}

13

Consider the statements:
x: The school bus arrived late
y: The student walked down to school
Which of the following can be represented by y ⇒ x?

• A. The school bus arrived early and Kate ran to school
• B. Mary walked to school because the school bus arrived late
• C. Either the school bus arrived late or Maryam walked to school
• D. Emmanuella did not go to school because the school bus arrived late

14

Differentiatef(x)=1(1−x2)5��������������(�)=1(1−�2)5 with respect to x�.

• A. −5x(1−x2)6−5�(1−�2)6
• B. −10x(1−x2)6−10�(1−�2)6
• C. 5x(1−x2)65�(1−�2)6
• D. 10x(1−x2)610�(1−�2)6

15

Express 33−√633−√6 in the form x+m√y�+�√�

• A. 3 – 3 √6
• B. 3 + 3√6
• C. 3 + √6
• D. 3 – √6

16

The table shows the mark obtained by students in a test.

If the mean mark is 3, find the value of k.

• A. 4
• B. 1
• C. 2
• D. 3

17

Simplify:log√27−log√8log3−log2��������:���√27−���√8���3−���2

• A. 3232
• B. -1414
• C. -3232
• D. 1414

18

Given that r = (10 N , 200º) and n = (16 N , 020º), find (3r – 2n).

• A. (62 N , 240º)
• B. (62 N , 200º)
• C. (62 N , 280º)
• D. (62 N , 020º)

19

Solve 6 sin 2θ tan θ = 4, where 0º < θ < 90º

• A. 18.43º
• B. 30.00º
• C. 35.26º
• D. 19.47º

20

An exponential sequence (G.P.) is given by 8√2, 16√2, 32√2, … . Find the nth�ℎ term of the sequence

• A. 82–√n82�
• B. 2(n+2)2–√2(�+2)2
• C. 2–√(n+3)2(�+3)
• D. 8n2–√

21

If f:x→2tanx�:�→2���� and g:x→√(x2+8),find(gof)(45o)�:�→√(�2+8),����(���)(45�)

• A. 4
• B. 2√3
• C. 6
• D. 3√2

22

A uniform beam PQ of length 80 cm and weight 60 N rests on a support at X where | PX | = 30 cm. If the body is kept in equilibrium by a mass m kg which is placed at P , calculate the value of m
[Take g = 10 ms−2−2]

• A. 2.0
• B. 3.0
• C. 2.5
• D. 4.0

23

An exponential sequence (G.P.) is given by 92,34,18,92,34,18,….Find its sum to infinity.

• A. 525525
• B. 415415
• C. 13121312
• D. 634634

24

Adu’s scores in five subjects in an examination are 85848386 and 87. Calculate the standard deviation.

• A. 2.0
• B. 1.4
• C. 1.8
• D. 1.6

25

In how many ways can a committee of 3 women and 2 men be chosen from a group of 7 men and 5 women?

• A. 500
• B. 350
• C. 720
• D. 210

26

Evaluate: ∫(2x+1)3dx∫(2�+1)3��

• A. 8(2x+1)2+k8(2�+1)2+�
• B. 6(2x+1)2+k6(2�+1)2+�
• C. 18(2x+1)4+k18(2�+1)4+�
• D. 16(2x+1)4+k16(2�+1)4+�

27

If α and β are the roots of 7×2+12x−4=07�2+12�−4=0,find the value of αβ(α+β)2αβ(α+β)2

• A. 736736
• B. -367367
• C. 367367
• D. -736736

28

If 3×2+px+12=03�2+��+12=0 has equal roots, find the values of p .

• A. ±12
• B. ±3
• C. ±4
• D. ±6

29

Given that 3x+4(x−2)(x+3)≡Px+3+Qx−23�+4(�−2)(�+3)≡��+3+��−2,find the value of Q.

• A. 2
• B. -2
• C. 1
• D. -1

30

The velocity of a body of mass 4.56 kg increases from (10ms−1,060o)to(50ms−1,060o)(10��−1,060�)��(50��−1,060�) in 16 seconds . Calculate the magnitude of force acting on it.

• A. 17.1 N
• B. 11.4 N
• C. 36.5 N
• D. 5.7 N

31

A linear transformation on the oxy plane is defined by P:(x,y)→(2x+y,−2y)�:(�,�)→(2�+�,−2�). Find P2�2

• A. [4104][4014]
• B. [4040][4400]
• C. [4004][4004]
• D. [4014][4104]

32

Given that y2+xy=5,finddydx�2+��=5,��������.

• A. y2y+x�2�+�
• B. −y2y+x−�2�+�
• C. −y2y−x−�2�−�
• D. y2y+x�2�+�

33

If X� and Y� are two independent events such that P(X)=18�(�)=18 and P(X⋃Y)=58�(�⋃�)=58, find P(Y)�(�).

• A. 1616
• B. 4747
• C. 421421
• D. 3737

34

A function f� is defined by f:x→x+2x−3,x≠3�:�→�+2�−3,�≠3.Find the inverse of f� .

• A. x+3x−2,x≠2�+3�−2,�≠2
• B. x−3x+2,x≠−2�−3�+2,�≠−2
• C. 3x−2x+1,x≠−13�−2�+1,�≠−1
• D. 3x+2x−1,x≠13�+2�−1,�≠1

35

The probabilities that Atta and Tunde will hit a target in a shooting contest are 1616 and 1919 respectively. Find the probability that only one of them will hit the target.

• A. 154154
• B. 41544154
• C. 20272027
• D. 1354

36

Given that p=[x347]Q=[x132x]�=[�437]�=[�312�] and the determinant of Q� is three more than that of P� , find the values of x�.

• A. −2,32−2,32
• B. 2,322,32
• C. −2,−32−2,−32
• D. 2−,322−,32

37

If m and ( m + 4) are the roots of 4×2−4x−15=04�2−4�−15=0, find the equation whose roots are 2 m and (2 m + 8).

• A. x2+8x−15=0�2+8�−15=0
• B. x2−2x−15=0�2−2�−15=0
• C. x2−8x−15=0�2−8�−15=0
• D. x2+2x+15=0�2+2�+15=0

38

Find the coefficient of the 6thterm6�ℎ���� in the binomial expansion of (1−2×3)10(1−2�3)10 in ascending powers of x�.

• A. −896×69−896�69
• B. −896×59−896�59
• C. −896×527−896�527
• D. −896×627−896�627

39

In how many ways can four Mathematicians be selected from six ?

• A. 90
• B. 60
• C. 15
• D. 360

40

If (x−5)(�−5) is a factor of x3−4×2−11x+30�3−4�2−11�+30, find the remaining factors.

• A. (x+3)and(x−2)(�+3)���(�−2)
• B. (x−3)and(x+2)(�−3)���(�+2)
• C. (x−3)and(x−2)(�−3)���(�−2)
• D. (x+3)and(x+2)

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## How to Answer JAMB Further Mathematics Questions

For every examination, there are/is principle(s) that must be followed by the candidates to ensure that the required level of success in the examination is achieved at the end.

In this section, I am going to reveal to you those principles that are applicable to JAMB Further Mathematics examination for an excellent performance.

First of all, I would like to let you know that it is possible to for a candidate to score 100% in JAMB Further Mathematics. That is, if such candidate follows the due rules and regulations required for answering the questions.

For those that would like to score above 300 in their UTME, it is advisable that you take the information contained in this section very serious.

The basic principles for answering JAMB chemistry questions are as follow:

1. Read Instructions

Once you login into the system and you have come to the chemistry section of the CBT, the next thing that you must do first is to read through the instructions on top of the page before you can proceed with reading the questions.

Most times, some instructions are specific to some questions, maybe one or two questions. Here, you still have to take those instructions very serious.

2. Read Carefully

Before you can proceed to answering JAMB Further Mathematics questions, it is highly recommended that you read carefully to understand any question before you can select answer for it.

It is possible to see questions that would be similar to what you have been seeing before, probably in past questions, but they are not the same.

This is the point where it pertinent that you meticulously go through the question before you answer, to avoid choosing the wrong option.

3. Start with the Simplest

The complexity of every question in JAMB Further Mathematics varies. After you have gone through the questions, you would be able to tell which of the questions are simple and the ones that are difficult.

The best approach in such case requires that you answer the questions from the simplest to the most complex ones. This is important because it will help to cushion you against examination tension.

Not only that, it also helps in the management of your time. If you are finding any question difficult to answer, you have to leave it and go to the next. Thereafter, you can re-visit those questions that you have left unanswered.

4. Attempt all the Question

Though it is advisable that you start answering your question from the simplest, leaving the more difficult ones at the first attempts, it does not imply that you should submit you examination without answering those ones you skipped.

It quite understandable that you may not know all the asked questions, you are still required choose your answers even the ones that you do not really know very well.

Sometime, your guess can fall in place and become the right answer. So always ensure that you attempt all you question before you submit.

5. Review your Answers

After you have attempted the entire given questions, you still have to go through all the 40 questions to check for any errors and possible corrections.

By going through the questions, you would be able to see any skipped question(s), if any and the ones you mistakenly clicked the wrong options.

6. Master your Shortcut Keys

As far as JAMB Computer Based Test is concerned, a good knowledge of the computer shortcut key is very important. Most times, the shortcut keys are given in the instruction section of the examination.

You have to get used to them so as to avoid using the wrong keys that will disrupt your examination. For instance, you might not mean to submit you examination but due to the lack of good understanding of the shortcut keys, you will mistakenly submit without completing your examination.

Also, there are times when your computer mouse may not be responding as expected. If you understand the keys very well, you will not have to worry yourself much. All you have to do is to switch from mouse click to using keys.

Some of the JAMB CBT keyboard guides are;

• – for option A
• – for option B
• – for option C
• – for option D
• – for next question
• – for previous question
• – for save and submit
• – for reverse, in case you saved by mistake without finishing you examination

You May Also Like:

Four Ways to Get Admission Without Using JAMB Score

How to Secure Admission with a Low UTME Score

I hope you have found this article useful. In case of any other questions about JAMB Further Mathematics Question and Answers 2024, kind make use of the comment sectrion below this article.

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